210+x^2=2000

Solution for 210+x^2=2000 equation:

210+x^2=2000

We move all terms to the left:

210+x^2-(2000)=0

We add all the numbers together, and all the variables

x^2-1790=0

a = 1; b = 0; c = -1790;
Δ = b2-4ac
Δ = 02-4·1·(-1790)
Δ = 7160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7160}=\sqrt{4*1790}=\sqrt{4}*\sqrt{1790}=2\sqrt{1790}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{1790}}{2*1}=\frac{0-2\sqrt{1790}}{2}
=-\frac{2\sqrt{1790}}{2}
=-\sqrt{1790}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{1790}}{2*1}=\frac{0+2\sqrt{1790}}{2}
=\frac{2\sqrt{1790}}{2}
=\sqrt{1790}
$